Least number k > 0 such that 3^k begins with exactly n consecutive increasing digits.

A244852

Least number k > 0 such that 3^k begins with exactly n consecutive increasing digits.

Terms

    a(0) =1a(1) =17a(2) =149a(3) =146a(4) =7997a(5) =45419a(6) =3972963a(7) =27487124a(8) =406680034

External references