Recurrence a(n+2) = (n+2)*a(n+1)*a(n), with a(0) = a(1) = 1.
A230053
Recurrence a(n+2) = (n+2)*a(n+1)*a(n), with a(0) = a(1) = 1.
Terms
- a(0) =1a(1) =1a(2) =2a(3) =6a(4) =48a(5) =1440a(6) =414720a(7) =4180377600
External references
- oeis: A230053
A230053
Recurrence a(n+2) = (n+2)*a(n+1)*a(n), with a(0) = a(1) = 1.