Numbers k such that there is a m with 2^m/(m+1) < binomial(m,k) <= 2^m/m and k < m/2.

Terms

a(0) =1a(1) =1a(2) =6a(3) =23a(4) =35a(5) =53a(6) =57a(7) =126a(8) =150a(9) =233a(10) =323a(11) =359a(12) =426a(13) =436a(14) =446a(15) =498a(16) =598a(17) =645a(18) =744a(19) =809a(20) =904a(21) =918a(22) =1063a(23) =1186a(24) =1348a(25) =1467a(26) =1756a(27) =2008a(28) =2028a(29) =2109