Numbers k such that tau(k+1) - tau(k) = 5, where tau(k) = the number of divisors of k (A000005).

Terms

a(0) =35a(1) =169a(2) =289a(3) =529a(4) =961a(5) =1369a(6) =2809a(7) =3135a(8) =4489a(9) =7921a(10) =9409a(11) =10609a(12) =10815a(13) =11881a(14) =12769a(15) =16129a(16) =18495a(17) =18769a(18) =22201a(19) =22801a(20) =26569a(21) =27889a(22) =32041a(23) =33855a(24) =38809a(25) =44521a(26) =49729a(27) =51529a(28) =52441a(29) =53823