Consider the succession rule (x, y, z) -> (z, y+z, x+y+z). Sequence gives z values starting at (0, 1, 2).

A219788

Consider the succession rule (x, y, z) -> (z, y+z, x+y+z). Sequence gives z values starting at (0, 1, 2).

Terms

    a(0) =2a(1) =3a(2) =8a(3) =17a(4) =39a(5) =87a(6) =196a(7) =440a(8) =989a(9) =2222a(10) =4993a(11) =11219a(12) =25209a(13) =56644a(14) =127278a(15) =285991a(16) =642616a(17) =1443945a(18) =3244515a(19) =7290359a(20) =16381288a(21) =36808420a(22) =82707769a(23) =185842670a(24) =417584689a(25) =938304279a(26) =2108350577a(27) =4737420744a(28) =10644887786a(29) =23918845739

External references