a(n) = F(2*n+1)^5 with n >= 0, F=A000045 (Fibonacci numbers).
A215045
a(n) = F(2*n+1)^5 with n >= 0, F=A000045 (Fibonacci numbers).
Terms
- a(0) =1a(1) =32a(2) =3125a(3) =371293a(4) =45435424a(5) =5584059449a(6) =686719856393
External references
- oeis: A215045