a(n)=(a(n-1)*a(n-2)^5+1)/a(n-3) with a(0)=a(1)=a(2)=1.
A208205
a(n)=(a(n-1)*a(n-2)^5+1)/a(n-3) with a(0)=a(1)=a(2)=1.
Terms
- a(0) =1a(1) =1a(2) =1a(3) =2a(4) =3a(5) =97a(6) =11786
External references
- oeis: A208205
A208205
a(n)=(a(n-1)*a(n-2)^5+1)/a(n-3) with a(0)=a(1)=a(2)=1.