For n>=0, let n!^(3) = A202368(n+1) and, for 0<=m<=n, C^(3)(n,m) = n!^(3)/(m!^(3)*(n-m)!^(3)). The sequence gives triangle of numbers C^(3)(n,m) with rows of length n+1.
A203484
For n>=0, let n!^(3) = A202368(n+1) and, for 0<=m<=n, C^(3)(n,m) = n!^(3)/(m!^(3)*(n-m)!^(3)). The sequence gives triangle of numbers C^(3)(n,m) with rows of length n+1.
Terms
- a(0) =1a(1) =1a(2) =1a(3) =1a(4) =42a(5) =1a(6) =1a(7) =5a(8) =5a(9) =1a(10) =1a(11) =1092a(12) =130a(13) =1092a(14) =1a(15) =1a(16) =1a(17) =26a(18) =26a(19) =1a(20) =1a(21) =1a(22) =11970a(23) =285a(24) =62244a(25) =285a(26) =11970a(27) =1a(28) =1a(29) =11
External references
- oeis: A203484