G.f. A(x) satisfies: A(x) = exp( Sum_{n>=1} B(x^n)/n ) where B(x) = Series_Reversion(x/A(x)) = g.f. of A179325.

A192637

G.f. A(x) satisfies: A(x) = exp( Sum_{n>=1} B(x^n)/n ) where B(x) = Series_Reversion(x/A(x)) = g.f. of A179325.

Terms

    a(0) =1a(1) =1a(2) =2a(3) =5a(4) =18a(5) =80a(6) =430a(7) =2590a(8) =17140a(9) =121992a(10) =923641a(11) =7375525a(12) =61742602a(13) =539333870a(14) =4898377418a(15) =46123950289a(16) =449236837762

External references