G.f. a(x) satisfies: A(x) = 1 + Sum_{n>=1} x^n*A(x)^A000265(n) where A000265(n) = largest odd divisor of n.
A191768
G.f. a(x) satisfies: A(x) = 1 + Sum_{n>=1} x^n*A(x)^A000265(n) where A000265(n) = largest odd divisor of n.
Terms
- a(0) =1a(1) =1a(2) =2a(3) =4a(4) =10a(5) =25a(6) =68a(7) =193a(8) =565a(9) =1688a(10) =5136a(11) =15854a(12) =49517a(13) =156191a(14) =496836a(15) =1591924a(16) =5133091a(17) =16643856a(18) =54234349a(19) =177505376a(20) =583272256a(21) =1923482331a(22) =6363842492a(23) =21117432227a(24) =70265970878a(25) =234388421515a(26) =783664894313
External references
- oeis: A191768