Numbers k such that tau(k-1) = (tau(k))^2 = tau(k+1), where tau(k) = A000005(k) (number of divisors of k).

A190266

Numbers k such that tau(k-1) = (tau(k))^2 = tau(k+1), where tau(k) = A000005(k) (number of divisors of k).

Terms

    a(0) =7a(1) =1241a(2) =1673a(3) =1751a(4) =1769a(5) =2471a(6) =2839a(7) =3161a(8) =3305a(9) =3497a(10) =3711a(11) =4135a(12) =4265a(13) =4279a(14) =4471a(15) =4711a(16) =5191a(17) =5433a(18) =5561a(19) =6017a(20) =6041a(21) =6103a(22) =6313a(23) =6809a(24) =6953a(25) =7031a(26) =7241a(27) =7463a(28) =7671a(29) =8023

External references