As p runs through the primes, sequence gives denominator of Sum_{k=1..p-1} 1/k^2.

A186720

As p runs through the primes, sequence gives denominator of Sum_{k=1..p-1} 1/k^2.

Terms

    a(0) =1a(1) =4a(2) =144a(3) =3600a(4) =1270080a(5) =153679680a(6) =519437318400

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