Consider the function f(n)=1/(Abs(n-r)), where r is the Dottie number, A003957. Let g(n) be defined by the recursion g(n)=Cos(g(n-1)),g(0)=1. Now, a(n)=floor(f(g(n))).

A180619

Consider the function f(n)=1/(Abs(n-r)), where r is the Dottie number, A003957. Let g(n) be defined by the recursion g(n)=Cos(g(n-1)),g(0)=1. Now, a(n)=floor(f(g(n))).

Terms

    a(0) =3a(1) =5a(2) =8a(3) =11a(4) =18a(5) =26a(6) =40a(7) =58a(8) =88a(9) =130a(10) =194a(11) =287a(12) =427a(13) =633a(14) =941a(15) =1396a(16) =2074a(17) =3078a(18) =4571a(19) =6785a(20) =10073a(21) =14954a(22) =22200a(23) =32957a(24) =48926a(25) =72632a(26) =107826a(27) =160071a(28) =237631a(29) =352771

External references