G.f. satisfies: [x^n] A(x)^(n+1) = [x^n] A(x)^(n+2) for n>1 with A'(0)=A(0)=1.

A177383

G.f. satisfies: [x^n] A(x)^(n+1) = [x^n] A(x)^(n+2) for n>1 with A'(0)=A(0)=1.

Terms

    a(0) =1a(1) =1a(2) =-3a(3) =18a(4) =-145a(5) =1398a(6) =-15330a(7) =186004a(8) =-2455893a(9) =34903110a(10) =-529903726a(11) =8547005820a(12) =-145847288730

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