Eight bishops and one elephant on a 3 X 3 chessboard: a(n) = 2^(n+2)-3*F(n+1), with F(n) = A000045(n).
A175661
Eight bishops and one elephant on a 3 X 3 chessboard: a(n) = 2^(n+2)-3*F(n+1), with F(n) = A000045(n).
Terms
- a(0) =1a(1) =5a(2) =10a(3) =23a(4) =49a(5) =104a(6) =217a(7) =449a(8) =922a(9) =1883a(10) =3829a(11) =7760a(12) =15685a(13) =31637a(14) =63706a(15) =128111a(16) =257353a(17) =516536a(18) =1036033a(19) =2076857a(20) =4161466a(21) =8335475a(22) =16691245a(23) =33415328a(24) =66883789a(25) =133853549a(26) =267846202a(27) =535917479a(28) =1072199137a(29) =2144987528
External references
- oeis: A175661