Eight bishops and one elephant on a 3 X 3 chessboard: a(n) = 3*2^n - 2*F(n+1), with F(n) = A000045(n).

A175657

Eight bishops and one elephant on a 3 X 3 chessboard: a(n) = 3*2^n - 2*F(n+1), with F(n) = A000045(n).

Terms

    a(0) =1a(1) =4a(2) =8a(3) =18a(4) =38a(5) =80a(6) =166a(7) =342a(8) =700a(9) =1426a(10) =2894a(11) =5856a(12) =11822a(13) =23822a(14) =47932a(15) =96330a(16) =193414a(17) =388048a(18) =778070a(19) =1559334a(20) =3123836a(21) =6256034a(22) =12525598a(23) =25073088a(24) =50181598a(25) =100420510a(26) =200933756a(27) =402017562a(28) =804277910a(29) =1608948656

External references