a(n) = 2^L(n+1) * 3^L(n)/12, where L(n) is the n-th Lucas number (A000032(n)).
A166473
a(n) = 2^L(n+1) * 3^L(n)/12, where L(n) is the n-th Lucas number (A000032(n)).
Terms
- a(0) =2a(1) =36a(2) =864a(3) =373248a(4) =3869835264
External references
- oeis: A166473