a(n) = 2^F(n+1)*3^F(n), where F(n) is the n-th Fibonacci number, A000045(n).
A166470
a(n) = 2^F(n+1)*3^F(n), where F(n) is the n-th Fibonacci number, A000045(n).
Terms
- a(0) =2a(1) =6a(2) =12a(3) =72a(4) =864a(5) =62208a(6) =53747712
External references
- oeis: A166470