Let the prime factorization of m be m = product p(m,k)^b(m,k), where p(m,j) < p(m, j+1) for all j, the p's are the distinct primes dividing m, and each b is a positive integer. Then a(n) = product {p(n,k)^b(A165713(n), k)}.

A165715

Let the prime factorization of m be m = product p(m,k)^b(m,k), where p(m,j) < p(m, j+1) for all j, the p's are the distinct primes dividing m, and each b is a positive integer. Then a(n) = product {p(n,k)^b(A165713(n), k)}.