a(n) = ((2^b-1)/phi(n))*Sum_{d|n} Moebius(n/d)*d^(b-1) for b = 9.

A160956

a(n) = ((2^b-1)/phi(n))*Sum_{d|n} Moebius(n/d)*d^(b-1) for b = 9.

Terms

    a(0) =511a(1) =130305a(2) =1676080a(3) =16679040a(4) =49902216a(5) =427400400a(6) =490968800a(7) =2134917120a(8) =3665586960a(9) =12725065080a(10) =10953738768a(11) =54707251200a(12) =34736533160a(13) =125197044000a(14) =163679268480a(15) =273269391360a(16) =222788253240a(17) =934724674800a(18) =482144484080

External references