a(n) = ((2^b-1)/phi(n))*Sum_{d|n} Moebius(n/d)*d^(b-1) for b = 5.

Terms

a(0) =31a(1) =465a(2) =1240a(3) =3720a(4) =4836a(5) =18600a(6) =12400a(7) =29760a(8) =33480a(9) =72540a(10) =45384a(11) =148800a(12) =73780a(13) =186000a(14) =193440a(15) =238080a(16) =161820a(17) =502200a(18) =224440a(19) =580320a(20) =496000a(21) =680760a(22) =394320a(23) =1190400a(24) =604500a(25) =1106700a(26) =903960a(27) =1488000a(28) =783060a(29) =2901600