Number of elements in the continued fraction for Sum_{k=0..n} 1/(1+2^(2^k)).

Terms

a(0) =2a(1) =4a(2) =8a(3) =15a(4) =24a(5) =41a(6) =85a(7) =159a(8) =314a(9) =651a(10) =1267a(11) =2496a(12) =4977a(13) =9889a(14) =19731a(15) =38945a(16) =77356a(17) =154693a(18) =308051a(19) =615768a(20) =1229080a(21) =2456328a(22) =4908126a(23) =9815038a(24) =19620985a(25) =39237465a(26) =78466413a(27) =156910438a(28) =313788371a(29) =627528817