G.f. A(x) satisfies: [x^n] A(x)^n = [x^n] A(x)^(n-1) for n>1 with A(0)=A'(0)=1.
A158882
G.f. A(x) satisfies: [x^n] A(x)^n = [x^n] A(x)^(n-1) for n>1 with A(0)=A'(0)=1.
Terms
- a(0) =1a(1) =1a(2) =-1a(3) =3a(4) =-13a(5) =71a(6) =-461a(7) =3447a(8) =-29093a(9) =273343a(10) =-2829325a(11) =31998903a(12) =-392743957a(13) =5201061455a(14) =-73943424413
External references
- oeis: A158882