G.f. satisfies: A(x) = B(x/A(x)) where A(x) = Sum_{n>=0} a(n)*x^n/[n!*(n+1)!/2^n] and B(x) = A(x*B(x)) = Sum_{n>=0} x^n/[n!*(n+1)!/2^n].
A155927
G.f. satisfies: A(x) = B(x/A(x)) where A(x) = Sum_{n>=0} a(n)*x^n/[n!*(n+1)!/2^n] and B(x) = A(x*B(x)) = Sum_{n>=0} x^n/[n!*(n+1)!/2^n].
Terms
- a(0) =1a(1) =1a(2) =-2a(3) =19a(4) =-379a(5) =12726a(6) =-641465a(7) =45181627a(8) =-4232016719a(9) =508271819428
External references
- oeis: A155927