Primes p such that continued fraction of (1 + sqrt(p))/2 has period 16 : primes in A146339.

Terms

a(0) =191a(1) =311a(2) =431a(3) =647a(4) =1319a(5) =1487a(6) =2351a(7) =5527a(8) =9431a(9) =19087a(10) =21143a(11) =24359a(12) =27239a(13) =29207a(14) =32183a(15) =34367a(16) =36791a(17) =38711a(18) =41759a(19) =42071a(20) =43063a(21) =43319a(22) =49367a(23) =58271a(24) =58391a(25) =59399a(26) =62327a(27) =65183a(28) =66239a(29) =77543