Primes p such that continued fraction of (1 + sqrt(p))/2 has period 8; primes in A146333.

Terms

a(0) =31a(1) =71a(2) =383a(3) =503a(4) =743a(5) =983a(6) =1327a(7) =2543a(8) =4271a(9) =5711a(10) =6151a(11) =8543a(12) =9871a(13) =14503a(14) =17783a(15) =21191a(16) =22031a(17) =25463a(18) =35023a(19) =35759a(20) =36263a(21) =36559a(22) =40543a(23) =46471a(24) =47711a(25) =60727a(26) =66343a(27) =72551a(28) =73751a(29) =75767