a(n) = Frobenius number for 4 successive primes = F[p(n), p(n+1), p(n+2), p(n+3)].

Terms

a(0) =1a(1) =4a(2) =9a(3) =23a(4) =42a(5) =67a(6) =83a(7) =101a(8) =125a(9) =199a(10) =262a(11) =335a(12) =367a(13) =393a(14) =492a(15) =593a(16) =704a(17) =807a(18) =873a(19) =990a(20) =817a(21) =950a(22) =1101a(23) =1353a(24) =2039a(25) =2624a(26) =2371a(27) =1494a(28) =1431a(29) =1640