a(n) = Frobenius number for 3 successive primes = F[p(n), p(n+1), p(n+2)].

Terms

a(0) =1a(1) =4a(2) =13a(3) =30a(4) =53a(5) =80a(6) =117a(7) =131a(8) =194a(9) =286a(10) =293a(11) =520a(12) =613a(13) =522a(14) =1310a(15) =858a(16) =1001a(17) =929a(18) =1610a(19) =1418a(20) =1322a(21) =1499a(22) =1421a(23) =2941a(24) =3300a(25) =3533a(26) =3710a(27) =3957a(28) =2065a(29) =2241