Define f(n) by e(n+1) = e(n) + 3^{n+1} - 1 + 2*f(n), where the rational numbers e(n) are defined in A134939; then a(n) is the numerator of f(n).
A134940
Define f(n) by e(n+1) = e(n) + 3^{n+1} - 1 + 2*f(n), where the rational numbers e(n) are defined in A134939; then a(n) is the numerator of f(n).
Terms
- a(0) =0a(1) =17a(2) =424a(3) =7889a(4) =131920a(5) =2099537a(6) =32570104a(7) =498191249a(8) =7559339680a(9) =114166849937
External references
- oeis: A134940