Start with a(1)=1; now a(n+1)=a(n)+a(k) with k=[n-n-th digit of Pi]. If k<0 or k=0, then a(k)=0.
A133389
Start with a(1)=1; now a(n+1)=a(n)+a(k) with k=[n-n-th digit of Pi]. If k<0 or k=0, then a(k)=0.
Terms
- a(0) =1a(1) =1a(2) =2a(3) =2a(4) =4a(5) =4a(6) =4a(7) =8a(8) =9a(9) =11a(10) =15a(11) =19a(12) =21a(13) =23a(14) =27a(15) =31a(16) =52a(17) =79a(18) =106a(19) =121a(20) =152a(21) =179a(22) =300a(23) =352a(24) =473a(25) =652a(26) =952a(27) =1058a(28) =1531a(29) =2483
External references
- oeis: A133389