Let df(n,k) = Product_{i=0..k-1} (n-i) be the descending factorial and let P(m,n) = df(n-1,m-1)^2*(2*n-m)/((m-1)!*m!). Sequence gives P(8,n).

A132466

Let df(n,k) = Product_{i=0..k-1} (n-i) be the descending factorial and let P(m,n) = df(n-1,m-1)^2*(2*n-m)/((m-1)!*m!). Sequence gives P(8,n).

Terms

    a(0) =0a(1) =0a(2) =0a(3) =0a(4) =0a(5) =0a(6) =0a(7) =1a(8) =80a(9) =1944a(10) =25200a(11) =217800a(12) =1411344a(13) =7361640a(14) =32391216a(15) =124227675a(16) =425339200a(17) =1323786464a(18) =3797876160a(19) =10155802176a(20) =25539739200a(21) =60844672800a(22) =138154965696a(23) =300509773245a(24) =628886888784

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