Least k>p such that (kp)^3 divides (p-1)^(kp)^2+1 for prime p = A000040(n).

Terms

a(0) =19a(1) =41a(2) =29a(3) =23a(4) =79a(5) =41617a(6) =20939a(7) =47a(8) =40427a(9) =4093a(10) =4441a(11) =2543a(12) =1033a(13) =659a(14) =2612032921a(15) =394502321a(16) =14958421a(17) =17957a(18) =569a(19) =14747a(20) =12641a(21) =167a(22) =174263a(23) =100493a(24) =285629