Half-indexed Fibonacci numbers a(n)=round(sqrt((1+sqrt(5))/2)^n/sqrt(5)) a(2n)=F(n)=A000045, so a(n)=F(n/2).
A127217
Half-indexed Fibonacci numbers a(n)=round(sqrt((1+sqrt(5))/2)^n/sqrt(5)) a(2n)=F(n)=A000045, so a(n)=F(n/2).
Terms
- a(0) =1a(1) =1a(2) =1a(3) =1a(4) =1a(5) =2a(6) =2a(7) =3a(8) =4a(9) =5a(10) =6a(11) =8a(12) =10a(13) =13a(14) =17a(15) =21a(16) =27a(17) =34a(18) =43a(19) =55a(20) =70a(21) =89a(22) =113a(23) =144a(24) =183a(25) =233a(26) =296a(27) =377a(28) =480a(29) =610
External references
- oeis: A127217