a(n) = (3*n^2 + 3*n + 1)*a(n-2), for n>2, with a(0) = a(1) = 1.

A123028

a(n) = (3*n^2 + 3*n + 1)*a(n-2), for n>2, with a(0) = a(1) = 1.

Terms

    a(0) =1a(1) =1a(2) =19a(3) =37a(4) =1159a(5) =3367a(6) =147193a(7) =569023a(8) =31940881a(9) =154205233a(10) =10572431611a(11) =61219477501

External references