10th-order Fibonacci numbers: a(n+1) = a(n)+...+a(n-9) with a(0) = ... = a(8) = 0, a(9) = 1.

A122265

10th-order Fibonacci numbers: a(n+1) = a(n)+...+a(n-9) with a(0) = ... = a(8) = 0, a(9) = 1.

Terms

    a(0) =0a(1) =0a(2) =0a(3) =0a(4) =0a(5) =0a(6) =0a(7) =0a(8) =0a(9) =1a(10) =1a(11) =2a(12) =4a(13) =8a(14) =16a(15) =32a(16) =64a(17) =128a(18) =256a(19) =512a(20) =1023a(21) =2045a(22) =4088a(23) =8172a(24) =16336a(25) =32656a(26) =65280a(27) =130496a(28) =260864a(29) =521472

External references