Matrix inverse of triangle A121335, where A121335(n,k) = C( n*(n+1)/2 + n-k + 1, n-k) for n>=k>=0.

Terms

a(0) =1a(1) =-3a(2) =1a(3) =0a(4) =-5a(5) =1a(6) =-12a(7) =4a(8) =-8a(9) =1a(10) =-129a(11) =-22a(12) =18a(13) =-12a(14) =1a(15) =-1785a(16) =-238a(17) =-51a(18) =51a(19) =-17a(20) =1a(21) =-30291a(22) =-3634a(23) =-345a(24) =-161a(25) =115a(26) =-23a(27) =1a(28) =-608565a(29) =-66750