a(1)=9; a(n)=floor((47+sum(a(1) to a(n-1)))/5).

Terms

a(0) =9a(1) =11a(2) =13a(3) =16a(4) =19a(5) =23a(6) =27a(7) =33a(8) =39a(9) =47a(10) =56a(11) =68a(12) =81a(13) =97a(14) =117a(15) =140a(16) =168a(17) =202a(18) =242a(19) =291a(20) =349a(21) =419a(22) =502a(23) =603a(24) =723a(25) =868a(26) =1042a(27) =1250a(28) =1500a(29) =1800