a(1)=8; a(n)=floor((41+sum(a(1) to a(n-1)))/5).

Terms

a(0) =8a(1) =9a(2) =11a(3) =13a(4) =16a(5) =19a(6) =23a(7) =28a(8) =33a(9) =40a(10) =48a(11) =57a(12) =69a(13) =83a(14) =99a(15) =119a(16) =143a(17) =171a(18) =206a(19) =247a(20) =296a(21) =355a(22) =426a(23) =512a(24) =614a(25) =737a(26) =884a(27) =1061a(28) =1273a(29) =1528