a(1)=7; a(n)=floor((35+sum(a(1) to a(n-1)))/5).

Terms

a(0) =7a(1) =8a(2) =10a(3) =12a(4) =14a(5) =17a(6) =20a(7) =24a(8) =29a(9) =35a(10) =42a(11) =50a(12) =60a(13) =72a(14) =87a(15) =104a(16) =125a(17) =150a(18) =180a(19) =216a(20) =259a(21) =311a(22) =373a(23) =448a(24) =537a(25) =645a(26) =774a(27) =928a(28) =1114a(29) =1337