Numerator of Sum[i=1..n] 1/(p(i)^p(i)), p(i) = i-th prime.
A117579
Numerator of Sum[i=1..n] 1/(p(i)^p(i)), p(i) = i-th prime.
Terms
- a(0) =1a(1) =31a(2) =96983a(3) =79870008269
External references
- oeis: A117579
A117579
Numerator of Sum[i=1..n] 1/(p(i)^p(i)), p(i) = i-th prime.