Numbers n such that (j^k + k^j) == 0 (mod k+j), j=4 case.

Terms

a(0) =1a(1) =4a(2) =12a(3) =25a(4) =28a(5) =30a(6) =60a(7) =61a(8) =109a(9) =124a(10) =252a(11) =478a(12) =529a(13) =1024a(14) =3273a(15) =6172a(16) =14881a(17) =24700a(18) =28732a(19) =29701a(20) =32509a(21) =41437a(22) =47569a(23) =70009a(24) =83209a(25) =86629a(26) =88177a(27) =99712a(28) =131161a(29) =161473