a(n)=1+floor(sqrt(Pi/2)*p(n)#).
A106558
a(n)=1+floor(sqrt(Pi/2)*p(n)#).
Terms
- a(0) =3a(1) =8a(2) =38a(3) =264a(4) =2896a(5) =37638a(6) =639830a(7) =12156759a(8) =279605448a(9) =8108557990a(10) =251365297667
External references
- oeis: A106558
A106558
a(n)=1+floor(sqrt(Pi/2)*p(n)#).