Define a(1)=0, a(2)=0, a(3)=15, a(4)=111 then a(n) = 254*a(n-2) - a(n-4) + 126 also sequence such that 7*a(n)*(a(n) + 1) + 1 = a square.
A105051
Define a(1)=0, a(2)=0, a(3)=15, a(4)=111 then a(n) = 254*a(n-2) - a(n-4) + 126 also sequence such that 7*a(n)*(a(n) + 1) + 1 = a square.
Terms
- a(0) =0a(1) =0a(2) =15a(3) =111a(4) =3936a(5) =28320a(6) =999855a(7) =7193295a(8) =253959360a(9) =1827068736a(10) =64504677711a(11) =464068265775
External references
- oeis: A105051