Let f(n)=mod(prime(n),12); then a(n) = binomial(prime(12),f(n)).

Terms

a(0) =666a(1) =7770a(2) =435897a(3) =10295472a(4) =854992152a(5) =37a(6) =435897a(7) =10295472a(8) =854992152a(9) =435897a(10) =10295472a(11) =37a(12) =435897a(13) =10295472a(14) =854992152a(15) =435897a(16) =854992152a(17) =37a(18) =10295472a(19) =854992152a(20) =37a(21) =10295472a(22) =854992152a(23) =435897a(24) =37a(25) =435897a(26) =10295472a(27) =854992152a(28) =37