Number of primes p(i) for i=1 to 20*10^n such that p(i+1)=p(i)+6 and p(i+2)=p(i)+12 and p(i+3)=p(i)+18, 4 consecutive primes in arithmetic progression 0 6 12 18.
A104062
Number of primes p(i) for i=1 to 20*10^n such that p(i+1)=p(i)+6 and p(i+2)=p(i)+12 and p(i+3)=p(i)+18, 4 consecutive primes in arithmetic progression 0 6 12 18.
Terms
- a(0) =1a(1) =12a(2) =64a(3) =416a(4) =2748a(5) =19348
External references
- oeis: A104062