a(1) = 1; for n >= 1, replace each part, with repetitions, of every part k in each partition of n with a(k), then take the sum to get a(n+1).

A096770

a(1) = 1; for n >= 1, replace each part, with repetitions, of every part k in each partition of n with a(k), then take the sum to get a(n+1).