If p(k) is the k-th prime, then the n-th set of 4 consecutive cousin prime pairs starts at p(a(n)).

Terms

a(0) =25a(1) =147a(2) =149a(3) =1828a(4) =1866a(5) =18814a(6) =20033a(7) =26397a(8) =57344a(9) =63654a(10) =71722a(11) =72982a(12) =76928a(13) =85072a(14) =99739a(15) =110985a(16) =122244a(17) =136645a(18) =145805a(19) =166884a(20) =183130a(21) =204206a(22) =244875a(23) =246292a(24) =256139a(25) =258721a(26) =258723a(27) =263243a(28) =296747a(29) =296749