If p(k) is the k-th prime, then the n-th set of 3 consecutive cousin prime pairs starts at p(a(n)).

Terms

a(0) =4a(1) =25a(2) =27a(3) =147a(4) =149a(5) =151a(6) =247a(7) =1037a(8) =1276a(9) =1828a(10) =1830a(11) =1866a(12) =1868a(13) =2198a(14) =3021a(15) =4012a(16) =4558a(17) =5543a(18) =6879a(19) =7381a(20) =10805a(21) =12701a(22) =17461a(23) =18136a(24) =18202a(25) =18814a(26) =18816a(27) =19121a(28) =19448a(29) =20033