Let a(1) = 1, a(2) = 2, a(3) = 7, a(4) = 15 and for n >= 5 set a(n) = (n*b(n) - b(n-2)) / 2, where b(n) = 4*b(n-2) - b(n-4) for n >= 5 and b(1) = 1, b(2) = 2, b(3) = 5, b(4) = 8.

A093652

Let a(1) = 1, a(2) = 2, a(3) = 7, a(4) = 15 and for n >= 5 set a(n) = (n*b(n) - b(n-2)) / 2, where b(n) = 4*b(n-2) - b(n-4) for n >= 5 and b(1) = 1, b(2) = 2, b(3) = 5, b(4) = 8.

Terms

    a(0) =1a(1) =2a(2) =7a(3) =15a(4) =45a(5) =86a(6) =239a(7) =433a(8) =1157a(9) =2034a(10) =5307a(11) =9151a(12) =23497a(13) =39974a(14) =101467a(15) =170913a(16) =430089a(17) =718946a(18) =1796975a(19) =2985775a(20) =7422437a(21) =12272502a(22) =30373191a(23) =50016721a(24) =123327373a(25) =202395986a(26) =497484067a(27) =814061151a(28) =1995542913a(29) =3257222726

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