a(n)*a(n-5) = a(n-1)*a(n-4)+a(n-2)+a(n-3), with initial terms a(1) = ... = a(5) = 1.

Terms

a(0) =1a(1) =1a(2) =1a(3) =1a(4) =1a(5) =3a(6) =5a(7) =9a(8) =17a(9) =65a(10) =117a(11) =227a(12) =449a(13) =1737a(14) =3137a(15) =6105a(16) =12097a(17) =46819a(18) =84565a(19) =164593a(20) =326161a(21) =1262361a(22) =2280101a(23) =4437891a(24) =8794241a(25) =34036913a(26) =61478145a(27) =119658449a(28) =237118337a(29) =917734275